SOLUTION: Please help me solve this word problem. A jet plane traveling at 500 mph overtakes a propeller plane, traveling at 200 mph, that had a 2 hour head start. How far from the starting

Algebra ->  Finance -> SOLUTION: Please help me solve this word problem. A jet plane traveling at 500 mph overtakes a propeller plane, traveling at 200 mph, that had a 2 hour head start. How far from the starting       Log On


   



Question 789956: Please help me solve this word problem. A jet plane traveling at 500 mph overtakes a propeller plane, traveling at 200 mph, that had a 2 hour head start. How far from the starting point are the planes? We have 5 tutors and we can't figure it out. Please Help! Michael Armani
Answer by josgarithmetic(39630) About Me  (Show Source):
You can put this solution on YOUR website!
The 200 mph plane traveled for h+2 hours, which shows the two-hour headstart. The 500 mph plane traveled for h hours. Are you given more information than you described in your help-request? Your five tutors could well have found the problem description to be incomplete, which is why they could not solve this problem. WHERE is the information about distance? None!

About the best you can analyze is like this:
Let the distance, still not given nor described, be d, and UNKNOWN for time.
Let the time for the 500 mph plane be h, UNKNOWN time in hours.

When the two planes reach the same place in their travel, we have
highlight%28500%2Ah=200%28h%2B2%29%29, which is simply EQUATING their traveled distance. Suddenly this appears to be solvable. That is one equation with only one unknown, d.

500h=200h%2B400
500h-200h=200h%2B400-200h
300h=400
h=4%2F3 HOURS, which is 1 hour 20 minutes.

With the time now known, you can compute the distance. Take your pick which expression:
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500(4/3)=667 miles
Or
200(2+4/3)=667 miles
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