Question 789804: A basketball team sells tickets that cost $10, $20, and VIP seats for $30. The team has sold 452 tickets overall. It has sold 87 more $20 tickets than $10 tickets. The total sales are $7650, how many tickets of each kind have been sold?
Ive been trying to put together an equation to figure this out but I just cant seem to figure it out. Could you please explain how I would put these into an equation? Thank you!
Answer by MathTherapy(10551)   (Show Source):
You can put this solution on YOUR website! A basketball team sells tickets that cost $10, $20, and VIP seats for $30. The team has sold 452 tickets overall. It has sold 87 more $20 tickets than $10 tickets. The total sales are $7650, how many tickets of each kind have been sold?
Ive been trying to put together an equation to figure this out but I just cant seem to figure it out. Could you please explain how I would put these into an equation? Thank you!
Let number of $10 and $30 tickets sold be C, and E, respectively
Then number of $20 tickets sold = C + 87
Therefore, C + C + 87 + E = 452 ------ 2C + E = 365 ----- eq (i)
Also, 10C + 20(C + 87) + 30E = 7,650 ----- 10C + 20C + 1,740 + 30E = 7,650 ----- 30C + 30E = 5,910 ------ 30(C + E) = 30(197)
C + E = 197 ------ eq (ii)
C = 168 ------- Subtracting eq (ii) from eq (i)
C, or number of $10 tickets sold = 
I'm sure you can find the number of $20 and $30 tickets sold.
After determining them, do a check!!
Further help is available, online or in-person, for a fee, obviously. Send comments, “thank-yous,” and inquiries to “D” at MathMadEzy@aol.com
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