SOLUTION: suppose a projectile is launched into the air from a platform. The formula h=-16t^2+40t+70 relates the height h of the object (in feet) and the time t since it was launched (in sec

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: suppose a projectile is launched into the air from a platform. The formula h=-16t^2+40t+70 relates the height h of the object (in feet) and the time t since it was launched (in sec      Log On


   

Question 789732: suppose a projectile is launched into the air from a platform. The formula h=-16t^2+40t+70 relates the height h of the object (in feet) and the time t since it was launched (in seconds). What is the maximum height the object reaches?
please help and explain because I can't figure this one out. Thanks in advance!
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
suppose a projectile is launched into the air from a platform. The formula h=-16t^2+40t+70 relates the height h of the object (in feet) and the time t since it was launched (in seconds). What is the maximum height the object reaches?
-------
h=-16t^2+40t+70
-------
Max height occurs where t = -b(2a) = -40/(2*-16) = 5/4
-----
Max height = h(5/4) = 95 ft.
--------------
Cheers,
Stan H.