SOLUTION: Let the width of a rectangle be w. The length of the rectangle is six less than double the width. A.) Write an equation to represent the area. B.) Write an expression to repres

Algebra ->  Rectangles -> SOLUTION: Let the width of a rectangle be w. The length of the rectangle is six less than double the width. A.) Write an equation to represent the area. B.) Write an expression to repres      Log On


   

Question 789724: Let the width of a rectangle be w. The length of the rectangle is six less than double the width.
A.) Write an equation to represent the area.
B.) Write an expression to represent the perimeter.
C.) Solve the equation if the perimeter is 30 inches.
D.) Tell the dimensions of the rectangle.
Answer by waynest(281) About Me  (Show Source):
You can put this solution on YOUR website!
l = 2w - 6
A.) A = lw
A = w(2w - 6)
A = 2w^2 - 6w
B.) P = 2L + 2w
P = 2(2w - 6) + 2w
P = (4w - 12) + 2w
P = 6w -12
C.) 30 = 6w - 12
30 + 12 = 6w - 12 + 12
42 = 6w
42/6 = 6w /6
7 = w
D.) width = 7 inches
length = 2(7) - 6 = 8 inches