Question 789478: 1/sec^2 40 + 1/csc^2 40
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! 1/sec^2 40 + 1/csc^2 40
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= (csc^2(40) + sec^2(40))/(sec^2(40)*csc^2(40))
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= csc^2(40) + sec^2(40)
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= (1/sin^2(40)) + (1/cos^2(40))
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= 1/(sin^2(40)cos^2(40))
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= 1/0.2425 = 4.1244
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Cheers,
Stan H.
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