SOLUTION: A quadratic function has its vertex at the point (0,1) . The function passes through the point (5,-8) . Find the quadratic and linear coefficients and the constant term of the fu

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: A quadratic function has its vertex at the point (0,1) . The function passes through the point (5,-8) . Find the quadratic and linear coefficients and the constant term of the fu      Log On


   

Question 788965: A quadratic function has its vertex at the point (0,1) . The function passes through the point (5,-8) . Find the quadratic and linear coefficients and the constant term of the function.
The quadratic coefficient is ______
The linear coefficient is _______
The constant term is ______
Answer by josgarithmetic(39614) About Me  (Show Source):
You can put this solution on YOUR website!
You want a parabola maybe?

y=a%28x-h%29%5E2%2Bk is standard form, and vertex is (h,k).

Using your given vertex, y=a%28x-0%29%5E2%2B1
y=ax%5E2%2B1.

Other given point on the graph is (5, -8), so put this into the equation and find a.
-8=a%2A5%5E2%2B1
-9=a%2A25
a=-9%2F25

The equation is highlight%28y=-%289%2F25%29x%5E2%2B1%29