SOLUTION: will someone check this for me please? sqrt{{{3x+9}}}+6=0 sqrt{{{3x+9}}}=-6 (sqrt3x+9}}})^2=(-6)^2 3x+9=36 3x=27 x=27

Algebra ->  Radicals -> SOLUTION: will someone check this for me please? sqrt{{{3x+9}}}+6=0 sqrt{{{3x+9}}}=-6 (sqrt3x+9}}})^2=(-6)^2 3x+9=36 3x=27 x=27      Log On


   

Question 78889: will someone check this for me please?
sqrt3x%2B9+6=0
sqrt3x%2B9=-6
(sqrt3x+9}}})^2=(-6)^2
3x+9=36
3x=27
x=27
Answer by tutor_paul(519) About Me  (Show Source):
You can put this solution on YOUR website!
You did fine until the very last step...
3x=27, so:
x=9
Good Job!
tutor_paul@yahoo.com