SOLUTION: You need 1425 mL of a 30% alcohol solution. On hand, you have a 5% alcohol mixture. How much of the 5% alcohol mixture and pure alcohol will you need to obtain the desired solution

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: You need 1425 mL of a 30% alcohol solution. On hand, you have a 5% alcohol mixture. How much of the 5% alcohol mixture and pure alcohol will you need to obtain the desired solution      Log On

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Question 788859: You need 1425 mL of a 30% alcohol solution. On hand, you have a 5% alcohol mixture. How much of the 5% alcohol mixture and pure alcohol will you need to obtain the desired solution?
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
H = 100% pure alcohol
T = 30% alcohol
L =5% alcohol
M = 1425 mL of mixture or solution at the 30% alcohol content
u = mL of 5% to use (unknown)
v = mL of pure alcohol (unknown)

These equations are your system.
%28Lu%2BHv%29%2FM=T and u%2Bv=M
Solve the system for u and v.