Question 787926: A movie theater has 2 ticket prices: 11$ for adults and 6$ for children. On a certain weekend, the theater sold 500 tickets for a total of 3900$. How many tickets of each kind were sold?
Answer by wilft1(217)   (Show Source):
You can put this solution on YOUR website! for this one your going to have to use 2 equations, you have 2 ticket prices that sold 500 total, so that equation will be
a + c = 500
second equation, adult ticket prices were 11 dollars, and children prices were 6 dollars, for a total of 3900 dollars, so that equation will be...
11a + 6c = 3900
lets solve using elimination method
a + c = 500
11a + 6c = 3900
we want to get rid of one of our variables, so lets multiply the top line by -6
-6a - 6c = -3000
11a + 6c = 3900
lets add the two lines up thereby eliminating 6c
5a = 900
divide both sides by 5
a = 180
now that we know the value of a, we can plug that into our original equation to find out the value of c
11(180) + 6c = 3900
1980 + 6c = 3900
6c = 1920
c = 320
plug in both values to doublecheck their accuracy, but your total ticket sales are....
180 adult tickets, and 320 children tickets.
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