SOLUTION: My question is:
Mary is three years older than her twin brothers. Next year, the sum of the ages will be exactly 102. How old are they now.
The Work I have is:
m=3+b
m+b+
Question 78788This question is from textbook Algebra
: My question is:
Mary is three years older than her twin brothers. Next year, the sum of the ages will be exactly 102. How old are they now.
The Work I have is:
m=3+b
m+b+w=102
3+b+b+w=102
3+2b+w=102 This question is from textbook Algebra
You can put this solution on YOUR website! Let M = Mary's present age.
Let B = One twin's present age.
Let W = Other twin's present age.
From the problem description, you can write:
M = B+3 and
(M+1)+(B+1)+(W+1) = 102 Why +1? Because next year they will all be 1 year older than they are now. Now substitute for the M = B+3, and since B=M (Twins would be the same age), you can rewrite the equation:
(B+3)+1 + B+1 + B+1 = 102 Simplify and solve for B
3B + 6 = 102 Subtract 6 from both sides.
3B = 96 Divide both sides by 3.
B = 32
The solution is:
Mary's age is 32+3 = 35 years.
One twin is 32 years.
The other twin is 32 years.
Check:
(M+1)+(B+1)+(W+1) = (35+1)+(32+1)(32+1) = 36+33+33 = 102 The sum of their ages next year.
You can put this solution on YOUR website! Mary is three years older than her twin brothers. Next year, the sum of the ages will be exactly 102. How old are they now.
The Work I have is:
m=3+b
m+b+b=102
3+b+b+b=102
3+3b=102
3b=99
b=33 (each of the twin brothers is 33)
Mary is 33+3=36
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Cheers,
Stan H.
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