SOLUTION: please help me solve
2 sin theta = 3 cot theta for 0<= theta<= 360 degrees
I think that it has something to do with making the two have the same base (cos or sin or something)
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-> SOLUTION: please help me solve
2 sin theta = 3 cot theta for 0<= theta<= 360 degrees
I think that it has something to do with making the two have the same base (cos or sin or something)
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Question 787811: please help me solve
2 sin theta = 3 cot theta for 0<= theta<= 360 degrees
I think that it has something to do with making the two have the same base (cos or sin or something) but I don't know what identity to use to get them to be like this! thank you! Answer by htmentor(1343) (Show Source):
You can put this solution on YOUR website! For simplicity, let x = theta
2sin(x) = 3cot(x)
Since cot(x) = cos(x)/sin(x) we have:
2sin(x) = 3cos(x)/sin(x)
2sin^2(x) = 3cos(x)
Now use the identity 1 - cos^2(x) = sin^2(x):
2(1-cos^2(x)) = 3cos(x)
2cos^2(x) + 3cos(x) - 2 = 0
This can be factored as
(2cos(x)-1)(cos(x)+2)
I'll leave it to you to complete the problem from here.
