SOLUTION: a tree of x meter high, the angle of elevation of its top from point P on the ground is 23 degree. From another point Q 10 meter from P and in line with P and the foot of the tree,
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Question 787642: a tree of x meter high, the angle of elevation of its top from point P on the ground is 23 degree. From another point Q 10 meter from P and in line with P and the foot of the tree, the angle of elevation is 32 degree. Find x. Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! a tree of x meter high, the angle of elevation of its top from point P on the ground is 23 degree. From another point Q 10 meter from P and in line with P and the foot of the tree, the angle of elevation is 32 degree. Find x.
Let the distance from P to the foot of the tree be y
so tan 23 = x/y
x= y Tan 23..................................(1)
so distance from foot of tree to Q = y-10
Tan 32 = x/(y-10)
x=(y-10)*tan 32........................(2)
equate (1) & (2)
y Tan 23 = (y-10)tan32
y*0.40 =(y-10)*0.63
0.4y=0.63y-6.3
0.63y-0.4y=6.3
0.23y=6.3
/0.23
y=27.4
Tan32 = x/27.4
0.63*27.4 = x
