You can put this solution on YOUR website! cot (cos^-1(-5/13))
&
sec (sin^-1 (x))
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let u=angle whose cos=(-5/13)
or cos(u)=(-5/13)
sin(u)=√(1-cos^2(x))=√(1-25/169)=√(144/169)=12/13
cot(u)=cos(u)/sin(u)=-5/12
..
let v=angle whose sin=x
or sin(v)=x
cos(v)=√(1-sin^2(v))=√(1-x^2)
sec(v)=1/cos(v)=1/√(1-x^2)
..
cot (cos^-1(-5/13))=-5/12
sec (sin^-1 (x))=1/√(1-x^2)
..
Note: the inverse of a trig function is always an angle
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