SOLUTION: A Man bought 3 houses for $440,000. 2nd house cost $6,000 more than the 1st 3rd house cost $4,000 more than the 2nd How much was the 1st?

Algebra ->  Expressions-with-variables -> SOLUTION: A Man bought 3 houses for $440,000. 2nd house cost $6,000 more than the 1st 3rd house cost $4,000 more than the 2nd How much was the 1st?      Log On


   

Question 787617: A Man bought 3 houses for $440,000.
2nd house cost $6,000 more than the 1st
3rd house cost $4,000 more than the 2nd
How much was the 1st?
Answer by harpazo(655) About Me  (Show Source):
You can put this solution on YOUR website!
x + (x + 6000) + (x + 6000) + 4000 = 440, 000
3x + 12,000 + 4,000 = 440,000
3x + 16,000 = 440,000
3x = 440,000-16,000
3x = 424,000
x = 424,000/3
x = 141,333.33
The payment for the first house is $141,333.33.
Understand?