Question 787538: Based on the equation, Z = (x - m)/sd and frequency distribution, please explain the answer to the following:
Bob takes an online IQ test and finds that his IQ according to the test is 134. Assuming that the mean IQ is 100, the standard deviation is 15, and the distribution of IQ scores is normal, what proportion of the population would score higher than Bob? Lower than Bob?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Based on the equation, Z = (x - m)/sd and frequency distribution, please explain the answer to the following:
Bob takes an online IQ test and finds that his IQ according to the test is 134. Assuming that the mean IQ is 100, the standard deviation is 15, and the distribution of IQ scores is normal, what proportion of the population would score higher than Bob? Lower than Bob?
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z(134) = (134-100)/15
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z(134) = 34/15 = 2.2667
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Proportion higher = P(z > 2.2667) = normalcdf(2.2667,100) = 1.17%
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Proportion lower = 100% - 1.17% = 98.83%
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Cheers,
Stan H.
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