SOLUTION: A right triangle has an area of 48cm^2 with one side that is twice as long as the other side. What is the hypotenuse of this triangle? The answer is 4 square foots 15.
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I kno
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Question 787187: A right triangle has an area of 48cm^2 with one side that is twice as long as the other side. What is the hypotenuse of this triangle? The answer is 4 square foots 15.
I know these formulas: A=1/2 the base*height and the pythagoream therom
a^2 + b^2 = c^2.
I was trying to solve by doing the following: 48= 1/2b * 2b; the "2's" cancel.
48=b*b -----> 48=b^2. I can place the 48 into the pythagoream therom; however, I still have 2 variables and I do not know how to solve. a^2 + 48 = c^2.
Thank you for your help.
Shanell Answer by Cromlix(4381) (Show Source):
You can put this solution on YOUR website! Hi Shanell,
If you make one of the sides of your
triangle = x.
And the other 2x (Twice the length)
Area of a triangle = 1/2(base * height)
48 = 1/2 (x * 2x)
48 = x^2
x =
So, one side of your triangle
would equal =
And the other side = 2 *
=
As you said Pythagoras =
a^2 + b^2 = c^2
Squaring a square root leaves the number
So, 48 + 192 = c^2
c^2 =
c = 4 square root 15.
Hope this helps.
:-)
