SOLUTION: please help me solve this application problem:
The speed of a passenger train is 10 mph faster than the speed of a freight train.The passenger train travels 340 miles in the same
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The speed of a passenger train is 10 mph faster than the speed of a freight train.The passenger train travels 340 miles in the same
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Question 786871: please help me solve this application problem:
The speed of a passenger train is 10 mph faster than the speed of a freight train.The passenger train travels 340 miles in the same time it take the freight train to travel 290 miles. Find the speed of each train.
WORK I'VE TRIED: Ptrain=s+10 Ftrain=s time=t(because they are traveling the same amount of time) and then i set up the equation 340/s+10=290/s
I can't seem to figure out the next steps. Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website! keep it separated mentally into:
(1) Equation for passenger train
(2) Equation for freight train
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Let = the time in hours for both trains
Let = the speed of the freight train
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Equation for passenger train:
(1)
Equation for freight train:
(2)
----------------
(1)
Substitute (2) into (1)
(1)
(1)
(1) hrs
and, since
(2)
(2)
(2)
(2)
The speed of the freight train is 58 mi/hr
The speed of the passenger train is 68 mi/hr
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check:
(1)
(1)
(1)
and
(2)
(2)
OK
