SOLUTION: A city ordinance requires a man to install a fence around a rectangular swimming pool. The pool is 16 feet wide nd 20 feet long. He has 154 feet worth of fencing. He wants to arran

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Question 786834: A city ordinance requires a man to install a fence around a rectangular swimming pool. The pool is 16 feet wide nd 20 feet long. He has 154 feet worth of fencing. He wants to arrange a rectangular fence so that each side of the fence is the same distance from the pool. Each side of the fence is x feet away, how do i solve for x. What is the equation as well.
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
The dimensions of the fence will be:
+16+%2B+2x+ by +20+%2B+2x+
The perimeter, +P+ is:
+P+=+2%2A%28+16+%2B+2x+%29+%2B+2%2A%28+20+%2B+2x+%29+
+P+=+32+%2B+4x+%2B+40+%2B+4x+
+P+=+8x+%2B+72+
You are given that +P+=+154+ ft
+8x+%2B+72+=+154+
+8x+=+82+
+x+=+10.25+
-------------
check:
+P+=+2%2A%28+16+%2B+2x+%29+%2B+2%2A%28+20+%2B+2x+%29+
+154+=+2%2A%28+16+%2B+2%2A10.25+%29+%2B+2%2A%28+20+%2B+2%2A10.25+%29+
+154+=+2%2A%28+16+%2B+20.5+%29+%2B+2%2A%28+20+%2B+20.5+%29+
+154+=+2%2A36.5+%2B+2%2A40.5+
+154+=+73+%2B+81+
+154+=+154+
OK