SOLUTION: Mar T. Ello participated in a triathlon in which he swam 3 miles, ran 5 miles and then bicycled 10 miles. Mar ran twice as fast as he swam, and he cycled three times as fast as he

Algebra ->  Rational-functions -> SOLUTION: Mar T. Ello participated in a triathlon in which he swam 3 miles, ran 5 miles and then bicycled 10 miles. Mar ran twice as fast as he swam, and he cycled three times as fast as he       Log On


   



Question 786489: Mar T. Ello participated in a triathlon in which he swam 3 miles, ran 5 miles and then bicycled 10 miles. Mar ran twice as fast as he swam, and he cycled three times as fast as he swam. If his total time for the triathlon was 1 hour and 46 minutes, then how fast did he swim?
Answer by Edwin McCravy(20056) About Me  (Show Source):
You can put this solution on YOUR website!
Mar T. Ello participated in a triathlon in which he swam 3 miles, ran 5 miles and then bicycled 10 miles. Mar ran twice as fast as he swam, and he cycled three times as fast as he swam. If his total time for the triathlon was 1 hour and 46 minutes, then how fast did he swim?
Let 

His swimming speed = x miles/hour

Mar ran twice as fast as he swam,
So

His running speed = 2x miles/hour

he cycled three times as fast as he swam
So 

His bicycling speed = 3x miles hour.

he swam 3 miles
Since TIME = DISTANCE%2FSPEED he swam for 3%2Fx of an hour

ran 5 miles
Since TIME = DISTANCE%2FSPEED he swam for 5%2F%282x%29 of an hour

and then bicycled 10 miles
Since TIME = DISTANCE%2FSPEED he swam for 10%2F%283x%29 of an hour

Total time = 3%2Fx%22%22%2B%22%225%2F%282x%29%22%22%2B%22%2210%2F%283x%29

his total time for the triathlon was 1 hour and 46 minutes
So we set the expression for the total time equal to 1%2646%2F60%22%22=%22%221%2623%2F30%22%22=%22%2253%2F30 hours

3%2Fx%22%22%2B%22%225%2F%282x%29%22%22%2B%22%2210%2F%283x%29 %22%22=%22%22 53%2F30

Clear of fractions by multiplying through by the LCD of 30x

90 + 75 + 100 = 53x
          265 = 53x
          265%2F53 = x
            5 = x

His swimming speed = x miles/hour = 5 miles/hour
His running speed = 2x miles/hour = 2(5) = 10 miles/hour
His bicycling speed = 3x miles hour = 3(5) = 15 miles/hour.

Edwin