Question 786283: A parking lot has a perimeter of 16000 feet. The width is 40 feet more than twice the length. what are the dimensions? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! A parking lot has a perimeter of 16000 feet. The width is 40 feet more than twice the length. what are the dimensions?
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P = 2(L + W)
16000 = 2(L + L+40)
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8000 = 2L + 40
2L = 7960
L = 3980 ft. (length)
W = L + 40 = 4020 ft. (width)
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Cheers,
Stan H.
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