SOLUTION: How do you complete the square for (((2x^2+3x+4=0)))?

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Question 78595: How do you complete the square for (((2x^2+3x+4=0)))?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
2x%5E2+%2B+3x+%2B+4+=+0
divide both sides by 2
x%5E2+%2B+%283%2F2%29x+%2B+2+=+0
subtract 2 from both sides
x%5E2+%2B+%283%2F2%29x+=+-2
divide the coefficient of x by 2, square it, and add it to both sides
x%5E2+%2B+%283%2F2%29x+%2B+9%2F16=+-2+%2B+9%2F16
%28x+%2B+%283%2F4%29%29%5E2+=+-23%2F16
If you take the square root of both sides,
the solution for x is imaginary