SOLUTION: I'm still a bit lost on this, how do I write the equation of the line L satisfying the given geometric conditions? L has y-intercept (0, 2) and is perpendicular to the line with

Algebra ->  Graphs -> SOLUTION: I'm still a bit lost on this, how do I write the equation of the line L satisfying the given geometric conditions? L has y-intercept (0, 2) and is perpendicular to the line with      Log On


   

Question 78579: I'm still a bit lost on this, how do I write the equation of the line L satisfying the given geometric conditions?
L has y-intercept (0, 2) and is perpendicular to the line with equation
2x - 3y = 6
Answer by checkley75(3666) About Me  (Show Source):
You can put this solution on YOUR website!
THE LINE PERPENDICULAR TO 2X+2Y=6 HAS A SLOPE THAT IS THE NEGATIVE RECIPRICAL OF THE SLOPE OF THIS LINE . THUS THE SLOPE OF THIS LINE IS
2X+2Y=6
2Y=-2X+6
Y=2X/2+6/2
Y=X+3 THIS LINE HAS A SLOPE OF 1. THEREFORE THE PERPENDICULAR LINE WILL HAVE A SLOPE (m) OF -1 & A Y INTERCEPT (b) OF 2.
THUS THE EQUATION IS
Y=-X+2
GRAPHING THESE TWO LINES WE GET
Y=2X+3 (RED LINE) & Y=-X+2 (GREEN LINE)
+graph%28+300%2C+300%2C+-8%2C+8%2C+-10%2C+10%2C+y+=+2x+%2B3%2C+y+=+-x+%2B2%29+ (graph 300x300 pixels, x from -8 to 8, y from -10 to 10, of TWO functions y = 2x +3 and y = -x +2).