SOLUTION: The sum of the digits of a three digit number is 12. The sum of the first digit and the last digit is twice that of the second digit. If the digits are reversed the new number is 1
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Question 785767: The sum of the digits of a three digit number is 12. The sum of the first digit and the last digit is twice that of the second digit. If the digits are reversed the new number is 198 more than the original number. Find the original number. Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! The sum of the digits of a three digit number is 12. The sum of the first digit and the last digit is twice that of the second digit. If the digits are reversed the new number is 198 more than the original number. Find the original number.
let the number be xyz
x+y+z=12..........................(1)
(x+z)=2y..........................(2)
100z+10y+x= 100x+10y+z+198
99z-99x=198.......................(3)
substitute x+z in (1)
2y+y=12
3y=12
y=4
so x+z=8...................(4)
multiply by 99
99x+99z=792
add this to (3)
198z=990
z=5
Now you can find x
so x=3
345 is the number
