SOLUTION: "The area of a triangular sheet of paper is 28 square inches. One side of the triangle is 2 inches more than three times the length of the altitude to that side. Find the length of

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Question 785757: "The area of a triangular sheet of paper is 28 square inches. One side of the triangle is 2 inches more than three times the length of the altitude to that side. Find the length of that side and the altitude to that side."
Can I get help setting up an equation and solving please?
Thank you for your time!!
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
"The area of a triangular sheet of paper is 28 square inches. One side of the triangle is 2 inches more than three times the length of the altitude to that side. Find the length of that side and the altitude to that side."

area of triangle = 28 jn^2
altitude=x
side = 3x+2
Area of Triangle = ?12 * base * altitude
28= 1/2 * x*(3x+2)
*2
56=x(3x+2)
56=3x^2+2x
3x^2+2x-56=0
Find the roots of the equation by quadratic formula

a= 3 , b= 2 , c= -56

b^2-4ac= 4 + 672
b^2-4ac= 676
%09sqrt%28%09676%09%29=%0926%09
x=%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29
x1=%28-b%2Bsqrt%28b%5E2-4ac%29%29%2F%282a%29
x1=( -2 + 26 )/ 6
x1= 4.00
x2=%28-b-sqrt%28b%5E2-4ac%29%29%2F%282a%29
x2=( -2 -26 ) / 6
x2= -4.67
ignore negative value
altitude = 4
base = 3x+2=> 3*4+2=14
CHECK
1/2 * 4*14
=28