2x³-4x+7x²+7 divide by x²+2x-1
Rearrange 2x³-4x+7x²+7 in descending powers 2x³+7x²-4x+7
Start with:
_____________
x²+2x-1)2x³+7x²-4x+7
Divide: 2x³÷x² = = 2x
Write 2x above -4x
2x
x²+2x-1)2x³+7x²-4x+7
Multiply 2x(x²+2x-1) = 2x³+4x²-2x and write
it below 2x³+7x²-4x and draw a line underneath
2x
x²+2x-1)2x³+7x²-4x+7
2x³+4x²-2x
Subtract (2x³+7x²-4x)-(2x³+4x²-2x) = 2x³+7x²-4x-2x³-4x²+2x = 3x²-2x
Write that below the line and bring down the next (last) term +7:
2x
x²+2x-1)2x³+7x²-4x+7
2x³+4x²-2x
3x²-2x+7
Divide: 3x²÷x² = = 3
Write +3 above the 7:
2x+3
x²+2x-1)2x³+7x²-4x+7
2x³+4x²-2x
3x²-2x+7
Multiply 3(x²+2x-1) = 3x²+6x-3 and write
it below 2x³+7x²-4x and draw a line underneath
2x+3
x²+2x-1)2x³+7x²-4x+7
2x³+4x²-2x
3x²-2x+7
3x²+6x-3
Subtract (3x²-2x+7)-(3x²+6x-3) = 3x²-2x+7-3x²-6x+3 = -8x+10
Write that below the line
2x+3
x²+2x-1)2x³+7x²-4x+7
2x³+4x²-2x
3x²-2x+7
3x²+6x-3
-8x+10
The answer is: = 2x+3 + .
Edwin
