SOLUTION: find x when the long leg is 4(x+2), the short leg is (x+3) and the hypotenuse is 25
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Question 785658
:
find x
when the long leg is 4(x+2), the short leg is (x+3) and the hypotenuse is 25
Answer by
xinxin(76)
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(4*(x+2))^2 + (x+3)^2 = 25^2
x = 4 or -8.12