SOLUTION: Carlos made a trip to the train station and back. The trip there took 4 hours and the trip back took 5 hours. He averaged 7 mph faster on the trip there than on the return trip. Wh

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Question 785611: Carlos made a trip to the train station and back. The trip there took 4 hours and the trip back took 5 hours. He averaged 7 mph faster on the trip there than on the return trip. What was Carly's average speed on the outbound trip?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Carlos made a trip to the train station and back. The trip there took 4 hours and the trip back took 5 hours. He averaged 7 mph faster on the trip there than on the return trip. What was Carly's average speed on the outbound trip?
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To the station DATA:
time = 4 hrs ; rate = x mph ; distance = r*t = 4x miles
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From the station DATA:
time = 5 hrs ; rate = x-7 mph ; distance = r*t = 5x-35 miles
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Equation:
distance = distance
4x = 5x-35
x = 35 mph (rate on the outbound trip)
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Cheers,
Stan H.
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