You can put this solution on YOUR website! solve 3sin(2x+40)=2cos(2x+40) where 0 < x <360
sub t for 2x+40 (saves typing)
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3sin(t) = 2cos(t)
9sin^2 = 4cos^2 = 4(1 - sin^2)
9sin^2 = 4 - 4sin^2
13sin^2 = 4
sin^2 = 4/13
sin(2x+40) = +2sqrt(13)/13
x = 356.845 degs
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sin(2x+40) = -2sqrt(13)/13
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x = 323.155 degs
