SOLUTION: Find the value of k so that the line containing the points (6,k) and (−7,−4) is parallel to the line containing the points (1,−9) and (4,−11).
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-> SOLUTION: Find the value of k so that the line containing the points (6,k) and (−7,−4) is parallel to the line containing the points (1,−9) and (4,−11).
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Question 785338: Find the value of k so that the line containing the points (6,k) and (−7,−4) is parallel to the line containing the points (1,−9) and (4,−11).
You can put this solution on YOUR website! the slope of line joining two points is given by the formula
(y2-y1)/(x2-x1)=m
x1 y1 x2 y2
1 -9 4 -11
slope m = (y2-y1)/(x2-x1)
( -11 - -9 )/( 4 - 1 )
( -2 / 3 )
m= - 2/ 3
A parallel line will have the same slope
(6,k) (-7,-4)
The line joining these points will have slope of -2/3
(-4-k)/(-7-6)=-2/3
(-4-k)/-13=-2/3
-4-k = -13*-2/3
-4-k = 26/3
k=-4-26/3
k=-38/3
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