SOLUTION: write the equation of a line perpendicular to the given line but passing through the given point y=-x+3; (-2,-2)

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Question 785081: write the equation of a line perpendicular to the given line but passing through the given point
y=-x+3; (-2,-2)
Answer by fcabanski(1391) About Me  (Show Source):
You can put this solution on YOUR website!
y = mx + b is the slope intercept form of a line equation. m is the slope. Parallel lines have the same slope.


y=-x+3 the slope is -1. So the slope of the parallel line is also 1.


y - y(1) = m(x-x(1)) is the point slope form of a line equation where (x(1),y(1)) is a point on the line, and m is the slope.


So the equation of this parallel line is y - (-2) = -1(x-(-2) which is y+2 = -x-2


We can write this in the slope intercept form by subtracting 2 from both sides.


y = -x - 4


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