SOLUTION: I've been working on this for about 15 minutes now and I can not seem to find an answer. Please help. The Murrays have invested money in two accounts. One pays 7% interest

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Question 7850: I've been working on this for about 15 minutes now and I can not seem to find an answer. Please help.

The Murrays have invested money in two accounts. One pays 7% interest and the other pays 8.5% interest. They invested $1000 more at 8.5% than they invested at 7%. If the total interest earned in one year is $395, how much money have they invested in each account.
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Let x = amount invested at 7%, then x+$1,000 = the amount invested at 8.5%.
Total interest earned = $395.00. Change the percents to decimals.
So, 0.07x+%2B+0.085%28x%2B1000%29+=+395
0.07x+%2B+0.085x+%2B+85+=+395 Simplify and solve for x.
0.155x+=+310
x+=+2000
So the Murrays invested $2,000.00 at 7% interest and $3,000.00 at 8.5% interest.
Check:
0.07($2,000.00) + 0.085($3,000.00) = $140.00 + $255.00 = $395.00