SOLUTION: find two consecutive natural numbers such that the difference of their reciprocals is 1/4 the reciprocal of the smallest number

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Question 784731: find two consecutive natural numbers such that the difference of their reciprocals is 1/4 the reciprocal of the smallest number
Answer by CubeyThePenguin(3113) About Me  (Show Source):
You can put this solution on YOUR website!
(duplicate question)
consecutive natural numbers: x, (x+1)
1/x - 1/(x+1) = 1/4x
4(x+1) - 4x = x+1
4x + 4 - 4x = x + 1
4 = x + 1
x = 3
numbers: 3, 4