SOLUTION: The figure shows the graph of the polynomial function y=f(x). For which of th values k=0,1,2,or 3 will the equation f(x) = k have complex roots? a. 0 b. 1 c. 2 d. 3 I am not

Algebra ->  Graphs -> SOLUTION: The figure shows the graph of the polynomial function y=f(x). For which of th values k=0,1,2,or 3 will the equation f(x) = k have complex roots? a. 0 b. 1 c. 2 d. 3 I am not       Log On


   

Question 78472: The figure shows the graph of the polynomial function y=f(x). For which of th values k=0,1,2,or 3 will the equation f(x) = k have complex roots?
a. 0
b. 1
c. 2
d. 3
I am not sure how to draw the graph to show what it looks like so I will try to explain it. The line comes up from the bottom of quadrant 3 and it goes to the right of (-1,-1)and continues up to (0,2)it then curves down thru (1,0)to (2,-2)and then curves up to just left of (3,0)and keeps going upward.
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
It sounds like you are describing a cubic ( a function with x%5E3 in it). Since I cannot see the graph, simply look at the graph and see if it intersects with these lines:
y=0, y=1, y=2, y=3
If it intersects in 3 places it will have 3 real roots. If it intersects at 1 place, then it will have 1 real root and 2 complex root. So if the graph intersects with say y=1 at one spot, then it will have 2 complex roots.