SOLUTION: solve the equation for 0◦≤ x ≤ 360◦ 4-sin theta= 4 cos ^2 theta. sorry kind of confused but think it has something to do with sin^2 theta + cos^2 theta=1 an
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-> SOLUTION: solve the equation for 0◦≤ x ≤ 360◦ 4-sin theta= 4 cos ^2 theta. sorry kind of confused but think it has something to do with sin^2 theta + cos^2 theta=1 an
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Question 784704: solve the equation for 0◦≤ x ≤ 360◦ 4-sin theta= 4 cos ^2 theta. sorry kind of confused but think it has something to do with sin^2 theta + cos^2 theta=1 and therefore cos^2 theta=1-sin^2 theta. does this mena that 1-sine theta= 4(1-sin^2theta)? thank you :) Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! solve the equation for 0◦≤ x ≤ 360◦ --
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4-sin(theta) = 4 cos^2(theta).
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Substitute for cos^2(theta):::
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4 - sin(theta) = 4[1-sin^2(theta)]
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4 - sin(theta) = 4 - 4sin^2(theta)
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4sin^2(theta) - sin(theta) = 0
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Factor:
sin(theta)[4sin(theta) - 1] = 0
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sin(theta) = 0 or 4sin(theta) = 1
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sin(theta) = 0 or sin(theta) = 1/4
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theta = 0 or 180 or 360 or 14.47 degrees or 165.52 degrees
Cheers,
Stan H.
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