SOLUTION: Find three consecutive integers such that twice the greatest integer is 2 less than 3 times the least integer.

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Question 784387: Find three consecutive integers such that twice the greatest integer is 2 less than 3 times the least integer.
Answer by CubeyThePenguin(3113) About Me  (Show Source):
You can put this solution on YOUR website!
consecutive integers: (x-1), x, (x+1)

2(x+1) = 3(x-1) - 2
2x + 2 = 3x - 5
-x = -7
x = 7

The integers are 6, 7, and 8.