SOLUTION: Find the equation of line going through (3,4) and (1,-1). This is what I've done so far: m= -1-4/1-3= -5/2 y-4= -5/2(x-3) -2(y-4)=-5(x-3) -2y+8=-5x+15 -8 -8 -2y/-

Algebra ->  Linear-equations -> SOLUTION: Find the equation of line going through (3,4) and (1,-1). This is what I've done so far: m= -1-4/1-3= -5/2 y-4= -5/2(x-3) -2(y-4)=-5(x-3) -2y+8=-5x+15 -8 -8 -2y/-      Log On


   

Question 784342: Find the equation of line going through (3,4) and (1,-1).
This is what I've done so far:
m= -1-4/1-3= -5/2
y-4= -5/2(x-3)
-2(y-4)=-5(x-3)
-2y+8=-5x+15
-8 -8
-2y/-2y=-5x/-2+7/-2
y=-5/2x+7/-2
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Find the equation of line going through (3,4) and (1,-1).
This is what I've done so far:
m= -1-4/1-3= -5/2 ************** = -5/-2 = 5/2
Use y = mx + b and either point to find b
4 = (5/2)*3 + b
b = -7/2
--> y = (5/2)x - 7/2
========================
This would work, but the slope is not right.
y-4= -5/2(x-3)
-2(y-4)=-5(x-3)
-2y+8=-5x+15
-8 -8
-2y/-2y=-5x/-2+7/-2
y=-5/2x+7/-2 ************* -5/2x could be (-5/2)x or -5/(2x). Add parentheses.