SOLUTION: Find three consecutive integers such that three times the least is 23 more than twice the greatest.

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Question 784262: Find three consecutive integers such that three times the least is 23 more than twice the greatest.
Answer by CubeyThePenguin(3113) About Me  (Show Source):
You can put this solution on YOUR website!
consecutive integers: (x-1), x, (x+1)

3(x-1) = 23 + 2(x + 1)
3x - 3 = 2x + 25
x = 28

The integers are 27, 28, and 29.