SOLUTION: Factor a^2(b-c)-16b^2(b-c)
Algebra
->
Polynomials-and-rational-expressions
-> SOLUTION: Factor a^2(b-c)-16b^2(b-c)
Log On
Algebra: Polynomials, rational expressions and equations
Section
Solvers
Solvers
Lessons
Lessons
Answers archive
Answers
Click here to see ALL problems on Polynomials-and-rational-expressions
Question 78386
:
Factor a^2(b-c)-16b^2(b-c)
Answer by
dolly(163)
(
Show Source
):
You can
put this solution on YOUR website!
a^2(b-c)-16b^2(b-c)
Here (b-c) is common to both the terms
==> (b-c)(a^2 - 16b^2)
==> (b-c)[(a)^2 - (4b)^2]
==> (b-c)(a+4b)(a-4b) [as a^2 - b^2 = (a+b)(a-b)]
Thus the factorized form is (b-c)(a+4b)(a-4b)