SOLUTION: Hi I would like some help in solving to find the x and y intercepts of the equation: y=x^2-6x+8
For the Y-intercept I was able to get that y=8 but I am not sure if that is right
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-> SOLUTION: Hi I would like some help in solving to find the x and y intercepts of the equation: y=x^2-6x+8
For the Y-intercept I was able to get that y=8 but I am not sure if that is right
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Question 783408: Hi I would like some help in solving to find the x and y intercepts of the equation: y=x^2-6x+8
For the Y-intercept I was able to get that y=8 but I am not sure if that is right and I cant solve for x. If you could help me that would be greatly appreciated. Answer by solver91311(24713) (Show Source):
No. Your -intercept is not right. An intercept is a point. A point in is designated by an ordered pair. The number 8 is not an ordered pair. The -coordinate of the -intercept is, indeed, 8. The -coordinate of any -intercept is zero. Hence your -intercept is the point .
To find the -intercepts, first find the zeros of the quadratic function. In other words, set the function equal to zero and solve by any convenient means. Hint: this one factors over the integers. Note that -2 times -4 = 8 and -2 plus -4 = -6. Once you have the two zeros of the function, and , you can form the ordered pairs that represent the two -intercepts thus:
John
Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it
