SOLUTION: I'm not sure how to solve this or where to even begin.
A chemist wants to dilute her 5L stock of 30% solution of acid to 15%. How much 10% solution does she have to add to the
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A chemist wants to dilute her 5L stock of 30% solution of acid to 15%. How much 10% solution does she have to add to the
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Question 783407: I'm not sure how to solve this or where to even begin.
A chemist wants to dilute her 5L stock of 30% solution of acid to 15%. How much 10% solution does she have to add to the 30% solution in order to obtain a mixture that is 15% acid? Found 2 solutions by josmiceli, solver91311:Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website! Let = liters of 10% solution to be added = liters of acid in 10% solution liters of acid already in 30% solution
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15 liters of 10% solution need to be added
check:
OK
The amount of pure acid in 5 liters of 30% solution is liters. The amount of pure acid in liters of 10% solution is liters. Mixed together, the amount of pure acid in liters of 15% solution is either or , so:
Solve for
John
Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it
