SOLUTION: 1. The sum of digits of a two digit positive integer is 11. If the digit at one's place is one less than the square of the digit at the ten's place. find the number?
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-> SOLUTION: 1. The sum of digits of a two digit positive integer is 11. If the digit at one's place is one less than the square of the digit at the ten's place. find the number?
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Question 782657: 1. The sum of digits of a two digit positive integer is 11. If the digit at one's place is one less than the square of the digit at the ten's place. find the number? Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! The sum of digits of a two digit positive integer is 11. If the digit at one's place is one less than the square of the digit at the ten's place. find the number?
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let u=units digit
let t= tens digit
u+t=11
u=11-t
..
u=t^2-1
11-t=t^2-1
t^2+t-11=0
(t+4)(t-3)=0
t=-4 (reject)
or
t=3
u=t^2-1=9-1=8
number: 38
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