SOLUTION: Suppose that Maria has 130 coins consisting of pennies, nickels, and dimes. The number of nickels she has is 9 less than twice the number of pennies; the number of dimes she has is
Algebra ->
Customizable Word Problem Solvers
-> Coins
-> SOLUTION: Suppose that Maria has 130 coins consisting of pennies, nickels, and dimes. The number of nickels she has is 9 less than twice the number of pennies; the number of dimes she has is
Log On
Question 782536: Suppose that Maria has 130 coins consisting of pennies, nickels, and dimes. The number of nickels she has is 9 less than twice the number of pennies; the number of dimes she has is 23 less than three times the number of pennies. How many coins of each kind does she have? Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! Suppose that Maria has 130 coins consisting of pennies, nickels, and dimes. The number of nickels she has is 9 less than twice the number of pennies; the number of dimes she has is 23 less than three times the number of pennies. How many coins of each kind does she have?
Pennies = x numbers
Nickels = 2x-9
Dimes = 3x-23
Add them up
x+2x-9+3x-23=130
6x-32=130
6x=130+32
6x=162
/6
x=27 ----------- pennies
substitute x to get the number of nickels and dimes
