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Question 782118: Find the equation of the line that passes through (4;-7) and is perpendicular to the line 2x - 5y = 3.
What is the vertex of y = 2 - 5x^2?
Which of the following points is not on the graph of y = (x - 3)^4?
(A) (0; 81) (B) (3; 0) (C) (4; 1)
(D) (2;��1) (E) None of these
Answer by mananth(16946)   (Show Source):
You can put this solution on YOUR website! 2 x + -5 y = 3
Find the slope of this line
-5 y = -2 x + 3
Divide by -5
y = 2/ 5 x + - 3/5
Compare this equation with y=mx+b, m= slope & b= y intercept
slope m = 2/5
The slope of a line perpendicular to the above line will be the negative reciprocal -5/2
Because m1*m2 =-1
The slope of the required line will be -5/2
m= -2 1/2 ,point ( 4 , -7 )
Find b by plugging the values of m & the point in
y=mx+b
-7 = -10 + b
b= 3
m= -5/2
The required equation is y = -5/ 2 x + 3
m.ananth@hotmail.ca
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