SOLUTION: Jack is 4 times as old as Lacy. 6 years from now the sum of their ages will be 67. How old are they now?

Algebra ->  Customizable Word Problem Solvers  -> Age -> SOLUTION: Jack is 4 times as old as Lacy. 6 years from now the sum of their ages will be 67. How old are they now?      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 781598: Jack is 4 times as old as Lacy. 6 years from now the sum of their ages will be 67. How old are they now?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Jack is 4 times as old as Lacy. 6 years from now the sum of their ages will be 67. How old are they now?
--------
Equations:
j = 4L
j+6 + L+6 = 67
======
Substitute for "j" and solve for "L"::
4L + 6 + L + 6 = 67
5L = 55
Lacy = 11 yrs (her age now)
-----
Jack = 4L = 44 yrs (his age now)
===========
Cheers,
Stan H.
============