Question 781544: Nate rolls a fair, six-sided die 5 times. What is the probability that he will get at least 2 evens? Answer by edjones(8007) (Show Source):
You can put this solution on YOUR website! nCr=n!/(r!(n-r)!)
5C0=.5^5=.031 none are even.
5C1=5*.5*.5^4=.156
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.031+.156=.1875 Less than 2 evens occur.
1-.1875=0.8125 the probability that he will get at least 2 evens.
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Ed
