Question 78147: How many gallons of a 70% alcohol solution must be mixed with 50 gallons of a 20% solution to obtain a solution that is 60% alcohol Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! How many gallons of a 70% alcohol solution must be mixed with 50 gallons of a 20% solution to obtain a solution that is 60% alcohol
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70% solution DATA:
Amount = x gallons ; Amt of alcohol = 0.70x gallons
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50% solution DATA:
Amount 50 gallons ; Amt of alcohol = 0.5(50) = 25 gallons
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Mixture DATA:
Amt = x+50 gallons ; Amt of alcohol = 0.60(x+50)= 0.6x+30 gallons
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alcohol + alcohol = alcohol
0.7x + 25 = 0.6x+30
0.1x =5
x=50 gallons (Amt of 70% solution that must be used.)
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Cheers,
Stan H.
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