SOLUTION: A box contains 3 red balls and 4 green balls. If two balls are randomly selected in sequence, what is the possibility that a red ball and a green ball are picked out of the box.
Algebra ->
Probability-and-statistics
-> SOLUTION: A box contains 3 red balls and 4 green balls. If two balls are randomly selected in sequence, what is the possibility that a red ball and a green ball are picked out of the box.
Log On
Question 781206: A box contains 3 red balls and 4 green balls. If two balls are randomly selected in sequence, what is the possibility that a red ball and a green ball are picked out of the box. State the rule for P(A&B) and then substitute the values and compute the answer. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! A box contains 3 red balls and 4 green balls. If two balls are randomly selected in sequence, what is the possibility that a red ball and a green ball are picked out of the box.
---------
# of ways to succeed: 3*4 = 12 pairs of red/green
----
# of possible pairs:: 7C2 = 21
------
P(red/gree pair) = 12/21 = 4/7
==================================
Cheers,
Stan H.
(