SOLUTION: y=1/4x-2; (8,-1) y=-4x-5; (0,-1) I am trying to understand these and write them out. However, the examples given are really no help to me and I keep coming up with different

Algebra ->  Linear-equations -> SOLUTION: y=1/4x-2; (8,-1) y=-4x-5; (0,-1) I am trying to understand these and write them out. However, the examples given are really no help to me and I keep coming up with different      Log On


   



Question 780921: y=1/4x-2; (8,-1)
y=-4x-5; (0,-1)
I am trying to understand these and write them out. However, the examples given are really no help to me and I keep coming up with different answers each time I work the problems. I am just getting back into school after 19 years. confused?

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
What you have is two linear ( straight line ) equations
A linear equation is also called a first order equation.
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The order of an equation is the highest power of +x+
You can think of these as:
(1) +y+=+%281%2F4%29%2Ax%5E1+-+2+
(2) +y+=+-4%2Ax%5E1+-+5+
As you can see, the order is +1+
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Straight lines stretch out to infinity in 2 directions, so
if you are given any +y+ value, you can find an +x+
I you are given any +x+, you can find a +y+
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I'm not sure what you're supposed to do with the given points.
(8,-1) is not on the line +y+=+%281%2F4%29%2Ax+-+2+
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You can plot a a point, though, and you can plot the lines.
Also, ( 0,-1) is not on the line +y+=+-4x+-+5+
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Here is a plot of both lines:
+graph%28+400%2C+400%2C+-10%2C+10%2C+-10%2C+10%2C+%281%2F4%29%2Ax+-+2%2C+-4x+-+5+%29+
The lines intersect at right angles. This is because the
slopes of the lines are negative reciprocals of eachother.
The slopes are:
+1%2F4+ and
+-4+
If the form of the equation is +y+=+m%2Ax+%2B+b+, then
+m+ is the slope
Hope this helps