SOLUTION: find two consecutive integers whose product exceeds their sum by 41

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: find two consecutive integers whose product exceeds their sum by 41      Log On


   

Question 780907: find two consecutive integers whose product exceeds their sum by 41
Answer by CubeyThePenguin(3113) About Me  (Show Source):
You can put this solution on YOUR website!
consecutive integers: x, (x+1)

x(x+1) = x + (x+1) + 41
x^2 + x = 2x + 42
x^2 - x - 42 = 0
(x - 7)(x + 6) = 0
x = 7, x = -6

The integers could be -6 and -5 or 7 and 8.