SOLUTION: If (log x)/2=(log y)/3=(log z)/5. then yz in term of x is

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Question 780850: If (log x)/2=(log y)/3=(log z)/5. then yz in term of x is
Answer by fcabanski(1391) About Me  (Show Source):
You can put this solution on YOUR website!
remember that a*log(b) = log%28%28b%5Ea%29%29

log(x)


log(x) = 2/3 * log(y) = log(y^(2/3)).


Remember if log(a) = log(b) then a=b


x = y^(2/3)


Similarly x = z^(2/5)


y^(2/3) * y^(1/3) = y. y^(1/3) = sqrt(x) so y = x*sqrt(x)


z^(2/5) * z^(2/5) * z^(1/5) = z. z^(2/5) = x, so that's x*x*sqrt(x) = x^2 * sqrt(x).


yz = x%2Asqrt%28x%29+%2A+x%5E2+%2A+sqrt%28x%29+=+x%5E4